RE: [vpFREE] Re: Here we go again?

Brian wrote: My biggest 50-play longshot was holding a pair of 2s and
getting SIX quads.

That's NOTHING. I once held a pair of 2s on a Fifty Play machine and
ended up with FIFTEEN quads!

Of course, I was playing NSU at the time. Do you think that matters?

Bob Dancer

For a 3-day free trial of Video Poker for Winners, the best video poker
computer trainer ever invented, go to //www.videopokerforwinners.com

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[vpFREE] Jean Scott's Frugal Vegas BLOG - 16 JAN 2008

Bringing out the Big Guns in the Casino Competition War

http://tinyurl.com/yw7bma

<a href="http://tinyurl.com/yw7bma">
http://tinyurl.com/yw7bma</a>

************************************************

This link is posted for informational purposes and doesn't
constitute an endorsement or approval of the linked article's
content by vpFREE. Any discussion of the article must be done
in accordance with vpFREE's rules and policies.

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Re: [vpFREE] Re: Here we go again...


Thanks, sounds good!

I neglected to divide my number (137,747,462) by Q^44 (.884901525). Doing so
gives your result. I think my number gives the chances of six OR MORE quads,
while yours gives the chances of EXACTLY six quads, which was what I was
after.

So, it's the product of--the probability of hitting the hand six times, the
probability of NOT hitting the hand 44 times, and the number of ways you can
arrange the six hits among the 50 hands. Sounds right to me!

No wonder I've only hit six quads once!

Brian

==========================================

In a message dated 1/16/2008 6:57:05 PM Pacific Standard Time,
jeff-cole@comcast.net writes:

bjaygold@... wrote:
My biggest 50-play longshot was holding a pair of 2s and getting SIX
quads. I could use some help with this one, as the number I come up
with is too high to be correct. I think.

and also wrote:
Here's how I calculated it.
Chances of hitting a quad from a pair is one in 360.333.
So, (360.333 ^ 6) / [50! / (44! * 6!)] = one in 137,747,462.
Did I calculate this correctly?

Brian, if we let P = 45/C(47, 3) [that's for the 360.333]
and let Q = 1 - P,
then C(50, 6) * P^6 * Q^44 gives us the probability of 6 hits, which
is 1/155,664,171. How does that sound?
Jeff

**************Start the year off right. Easy ways to stay in shape.
http://body.aol.com/fitness/winter-exercise?NCID=aolcmp00300000002489

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[vpFREE] Personal Comments

> Please remove your fingers from the keyboard,
> and remove your head from your ass.

Negative personal comments won't be tolerated on vpFREE.
Please keep things impersonal, and address the message
rather than the messenger, or use the delete key.

vpFREE Administrator

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[vpFREE] (Fwd) Caesars LV

Private email to vpFae:

Hi,

What's the deal with Caesars? Skip Hughes has in his LVA column
that there are two $1/2/5 9/6 Jacks 3/5 plays in the Palace
casino. The database is supposedly monitored but mentions
nothing.

There is so little to play at any Harrahs property.

PLEASE check this out. A more precise location would also help.

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[vpFREE] New poll for vpFREE


Enter your vote today! A new poll has been created for the
vpFREE group:

Do you adjust your strategy when playing progressives?


o I use the same strategy I would use if it wasn't a progressive.
o I make a few strategy adjustments when playing progressives.
o I make a lot of strategy adjustments when playing progressives.
o I make (or try to make) all applicable strategy adjustments when playing progressives.

To vote, please visit the following web page:
http://groups.yahoo.com/group/vpFREE/surveys?id=12704745

Note: Please do not reply to this message. Poll votes are
not collected via email. To vote, you must go to the Yahoo! Groups
web site listed above.

Thanks!

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[vpFREE] New poll for vpFREE


Enter your vote today! A new poll has been created for the
vpFREE group:

How much do you estimate that you play progressives?


o I don't play progressives.
o From 1% to 25% of my coin-in is on progressives.
o From 26% to 50% of my coin-in is on progressives.
o From 51% to 75% of my coin-in is on progressives.
o From 76% to 99% of my coin-in is on progressives.
o I only play progressives.

To vote, please visit the following web page:
http://groups.yahoo.com/group/vpFREE/surveys?id=12704743

Note: Please do not reply to this message. Poll votes are
not collected via email. To vote, you must go to the Yahoo! Groups
web site listed above.

Thanks!

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[vpFREE] Re: Treasure Island Las Vegas

--- In vpFREE@yahoogroups.com, "what7do7you7want" wrote:
> Actually.... Its not.... In fact, decimationg a player's bankroll is
probably bad for business. That player may actually QUIT playing for
good. That player will probably not want to play there again, even if
he does play again. > Quadzilla
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
REPLY: Correct!

But I think that the poster assumes levels of knowledge and rationality
rarely possessed by slot managers -- and clearly not possessed by TI's
slot managerds.

Aside: Maybe TI's total revenues would increase if they cleaned out
the visible mold in their guest-room bathrooms.

The GMan

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[vpFREE] Re:Rob Singer and Hillary Clinton are ACTUALLY THE SAME PERSON!!!

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[vpFREE] Re: A Stupid Bankroll Qestion

Gambling bankroll is the amount of your savings (you have savings,
right?) that you allocate to gambling. If you're a pro and know what
you're doing, it could be all of your savings, but it really shouldn't
be. If you don't know what your bankroll is, then it is probably all
the cash you can get your hands on, by pawning off everything and
selling your soul, etc. If you say, oh no, I'm not addicted to
gambling, I would definitely stop at X dollars, at least for a couple
of years until I built my savings back up (you do save, right?), well
then X is your bankroll. If you're smart, you Kelly bet, a lot of
people do this naturally. Say for example, your gambling bankroll is
eight thousand. You should go play quarter deuces. If you don't make
any mistakes and get lucky and double up your bankroll before the
casino notices and tries to shake you down for your bankroll, it's
time to move up to fidy-cent deuces. But if your bankroll dribbles
down to four thousand, either because of bad luck or you've got a leak
somewhere, it's time to move down to nickel deuces, 12 coins in. If
your rich uncle dies and leaves you his bankroll, you can move up, on
the other hand if your daughter convinces you to pay for her wedding,
you get to move down, etc. It's not rocket science and there's no
magic, it takes money to win money. When you get to the point that you
can live off the interest your bankroll generates, then you have
financial freedom.

--- In vpFREE@yahoogroups.com, BANDSTAND54@... wrote:
>
> Howdy
>
> Is a lifetime bankroll the same as a long term bankroll?
>
> Grumpy
>
>
>
> **************Start the year off right. Easy ways to stay in shape.

> http://body.aol.com/fitness/winter-exercise?NCID=aolcmp00300000002489
>
>
> [Non-text portions of this message have been removed]
>

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[vpFREE] Re: Here we go again? REALLYSICKANDTIRED

In a message dated 1/16/2008 9:26:43 A.M. Pacific Standard Time,
skiphughes@cox.net writes:

For whomever posted the original question (or anyone else), think of
it this way.

You are playing a 1 million-play machine. (And don't quibble, people.
Assume that's the number required)
...............................
Yes. I was maybe the first responder to the latest denny.dork troll post. I
stated the same thing as above only in the form of running 10*100k autoplays
on any game using WinPoker. 1 million total plays would give you almost
exactly the EV of the game.

I've been on the Internet since 96' and have only encountered one worse
troll than [sounds like] Blob Dinger. A guy named Kevin Yorindo from Panama Beach
Florida harassed AOL recovery chat up to 5 hrs a day. He actually began
harassing police chat with the screen name "SWINEHATER" but the cops sent him a
message so to speak so he found a softer target, recovery chat. His accounts
were canceled frequently and he came back with new accounts and new screen
names. He started a website named "AADEPROGRAMING" Everything he said was a flat
out lie just like Blob Dinger. After several years of evilness he committed
suicide by hanging himself.

I'm calling upon any vpFREE member who is as sick and tired of the wave
after wave of "RND is not random" and "Short term vs long term" troll posts as I
am to send an email to the list owner demanding the removal of [sounds like]
Blob Dinger from the vpFREE links to "Video Poker Writers" and to quickly ban
IP addresses of any new troll poster.
Drained and Bramaged
p.s If you don't like my opinion or my humor then please blocker me up with
your spam controls.


**************Start the year off right. Easy ways to stay in shape.
http://body.aol.com/fitness/winter-exercise?NCID=aolcmp00300000002489

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[vpFREE] Re: Palazzo Snubs Grazie Gold Players?

I can confirm last night when I asked about the Gold Lounge at
Pallazzo, they told me it was a Platinum Lounge only, for Gold I had to
go over to the Venetian.

--- In vpFREE@yahoogroups.com, "npf152512" <npf152512@...> wrote:
>
> A friend emailed me today that the lounge in the new Venetian Palazzo
> admits only Platinum level players. For those not familiar, that
> level is reached now at well over $1 million coin-in annually.
>

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[vpFREE] Re: Here we go again?

cdfsrule wrote:
>
> Yes, here we go again and again...
>
> Harry Porterwrote:
> > Variance, as a mathematical measure, best describes the range of
> > outcomes for an event that has a true "normal" distribution (e.g.
> > the flipping of a penny or roll of a die).
>
> Neither the flipping of a penny nor the roll of a die produces a
> "normal" distribution of outcomes (normal meaning gaussian or
> bell-curve). Not even close. Both should produce even distributions
> (discrete even distributions).
>
> If you summed the output of multiple rolls, or multiple die, as the
> number things you summed increases, the distribution would begin to
> look more "normal". In that case, the standard deviation would go as
> 1/sqrt(N) where N is the number of rolls you summed up, since there
> is NO correlation between die.

Yes, perhaps, here we go again (and again) ...

Unless I'm mistaken, it would seem that my wording wasn't precise
enough for you (or, to be more specific, that in an atypical manner I
spared a few too many words and made erred by presuming that what was
missing would be inferred).

You're absolutely correct, if you chart the distribution of heads vs.
tails in multiple flips of a coin, you'd expect an even distribution
... that is, the number of each should be roughly even. This can also
be referred to as a discrete uniform distribution (I had to look that
one up).

What I had in mind was the distribution of the cumulative number of
observed heads (or tails) as the number of flips increases. But once
again, I'm imprecise in describing this as a normal distribution ...
for the term "normal distribution" describes a continuous probability
distribution -- were the distribution of head tosses truly a normal
distribution (rather than a discrete distribution), then there would
be a probability assigned for an event such as 5.363 heads being observed.

To be more accurate, I should have said that the two examples were
discrete distributions that approximate a normal distribution (to
again make the distinction in my post that vp results, instead, do not).

Now, certainly this more accurately presents the information (although
I have no doubt that if you're inclined to do so, you can still point
to some inaccuracies). My suspicion, however, is that most here would
prefer that you not encourage me in going on at such length when it
doesn't really add much clarity to my original point (as far as the
vpFREE rank and file go).

- H.

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