Earlier, I wrote:
My biggest 50-play longshot was holding a pair of 2s and getting SIX quads.
I could use some help with this one, as the number I come up with is too high
to be correct. I think.
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Here's how I calculated it.
Chances of hitting a quad from a pair is one in 360.333.
So, (360.333 ^ 6) / [50! / (44! * 6!)] = one in 137,747,462.
Did I calculate this correctly?
Thanks,
Brian
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