Re: [vpFREE] Re: My Casino Henderson

 

thank you


---In vpFREE@yahoogroups.com, <vegasvpplayer@...> wrote :

It wasn't a get rich play, but was a positive play if you restricted play to 5X point days or when they had a bonus promotion with free play or gift cards. Best game is $2 8/6 BPD and until a few months ago 50c pNSUD Five Play. Top monthly mailer was 4 x $75.





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Posted by: bobbartop@yahoo.com
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Re: [vpFREE] Re: My Casino Henderson

 

It wasn't a get rich play, but was a positive play if you restricted play to 5X point days or when they had a bonus promotion with free play or gift cards. Best game is $2 8/6 BPD and until a few months ago 50c pNSUD Five Play. Top monthly mailer was 4 x $75.

Sent from my iPhone

> On Apr 8, 2015, at 1:07 PM, bobbartop@yahoo.com [vpFREE] <vpFREE@yahoogroups.com> wrote:
>
> Not surprised. The last time I was there their paytables were lousy. They had progressives, also lousy. To say it was not competitive in a competitive area (Boulder Hwy) is an understatement.
>
>
>
>

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Re: [vpFREE] Re: A Keno Math Problem

 


I believe this suggests that we're on a similar wavelength now ;)

For the skillful, I suspect there's some elegant math that might be applied to simplify the solution. It's beyond me, however. I advise simulation.

My hands are full presently, but I may take a crack at an estimate and post back.



---In vpFREE@yahoogroups.com, <Nordo123@...> wrote :

I think I am beginning to understand this problem. Without the guarantee you are right Harry this is a complex problem that can't be solved in closed form. Without the guarantee let P(n) stand for the probability that in your last n games you have a 60 game losing streak. It is obvious that P(n) = P(n-1) + ((1-P(n-61))x(0.04324789135)x(0.070463738969)). This involves solving a 61st degree polynomial which can not be solved in closed form. To get you started P(60) = 0.070463738969, P(61) = P(60) + (0.04324789135)x(0.070463738969) = 0.07351114706. Years ago I solved the problem of a baseball team in n games having a 2 game winning (or losing) streak with the probability of a win or a loss a constant with independence of games. This involved solving a cubic equation which can be solved. It still took me a few days to put this in closed form. Good luck on this one Mickey!

Sent from my iPhone


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Re: [vpFREE] Xvp suicide at M

 

I totally agree

Sent from my iPad

> On Apr 8, 2015, at 9:29 PM, Misscraps misscraps@aol.com [vpFREE] <vpFREE@yahoogroups.com> wrote:
>
> A normal person wouldnt kill themselves over a loss of free buffets. What a normal person would do is sue. Obviously this man had some emotional problems. Maybe the loss of the buffets was a trigger that pushed him over the edge, but it certainly didn't "cause" a suicide.
>
>

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[vpFREE] Xvp suicide at M

 

A normal person wouldnt kill themselves over a loss of free buffets. What a normal person would do is sue. Obviously this man had some emotional problems. Maybe the loss of the buffets was a trigger that pushed him over the edge, but it certainly didn't "cause" a suicide.

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Re: [vpFREE] Re: A Keno Math Problem

 

Combining the previous 4 tabs where you are awarded multipliers, extra draws and bets, with the payscale I have moved the payback up to 78%. The next four tabs are where the money comes in. I earlier described the box on the upper left with the 5 free games, 2X multiplier, and 3 extra draws. These are actually meters. Here are the final 4 tabs.

Blue Tab: Catching this tab increases thr Free Games meter by 1 game. So if it is sitting on 5 it will move to 6. If it is sitting on 6 it will move to 7, etc. It caps at 60 free games. If you dont catch a 3/4 in the next 60 games you are automatically awarded a new tab.

Orange Tab: Increases the Multiplier meter by 1. If its on 2X it moves to 3X. If its on 3X it moves to 4X. It caps at 20X. No 3/4 in 60 games and you are awarded a new tab.

Purple Tab: Increases the Extra Draws meter by 1. If its sitting on 3 it moves to 4. If its sitting on 4 it moves to 5. Caps at 40 extra draws.

Pink Tab: Increases the progressive meter by 4 bets. Not catching a 3/4 in 60 games awards you a new tab.

So to me the trick to this game is finding it where the ploppies have built up the meters and walked off. Like finding it with 10 free games, a 10X multiplier, and 10 extra draws.
I'll get to this in later posts.

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Re: [vpFREE] Re: A Keno Math Problem

 

After reading sayitsme and vp wiz I think I'm going to let the frequency stand at 23.12 in analyzing the play. I always come up with minimum playable numbers. Leaving the frequency where it is will be a slight error that favors me.

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[vpFREE] Daily Tier Bonus/Fuel Rewards Network

 

Due to Total Rewards system maintenance, you will not receive Daily Tier
Credit Bonus/Fuel Rewards Savings notification emails between now and April
13. Even though you will not receive a notification email, you are still
receiving your earned Tier Credit Bonuses and/or Fuel Rewards and they are
being posted to your account.

Darryl

*Darryl D. McEwen, Publisherhttp://www.sevenstarsinsider.com
<http://www.sevenstarsinsider.com>*

*Click here
<https://sites.google.com/site/sevenstarsinsider/latest-news-about-caesars-entertainment>
for latest news about Caesars Entertainment*

*Follow us on Twitter: @7StarsInsider*

*Read my Mr. AC Casino
<http://www.pressofatlanticcity.com/attheshore/blogs/mr_ac_casino/> column
in At The Shore*

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Re: [vpFREE] Re: A Keno Math Problem

 

So I described what happens when you hit all four machine picks. Here's the payscale for the 7 spot

3/7.......1
4/7.......4
5/7.......9
6/7.....40
7/7...366

It comes in at 50%.

Now, when you hit 3 of the 4 machine picks there are 8 different events that, according to the rules screen, are equally likely to happen. A color coded tab will jump up and award certain something.

Red Tab: You are awarded either 2X or 3X pay with 2 extra draws until the next 3/4 hits.
This feature is not capped at 60 games. I had to do an empirical here. The 2X and 3X multipliers are not equally likely to occur. Through 186 catches I caught the 2X 152 times and only caught the 3X 34 times.

Green Tab: You are awarded from 5 to 15 bets. I did an empirical on it. Its weighted random and averages 7.5 bets. Once you are awarded the green tab if you dont hit 3/4 in 60 games you are automatically awarded another tab.

Yellow Tab: You are awarded either a 2X, 3X,4X or 5X multiplier until the next 3/4 hits. I have an empirical going. Through 68 catches I caught the 2X 51 times, 3X 8 times, 4X 5 times, and the 5X 4 times. You are not capped at 60 games when in yellow.

Aqua Tab: You are awarded either 3,4, 5, 6, or 8 extra draws until the next 3/4 hits. This is not purely random either. Through 125 catches I caught the 3 a total of 33 times, the 4 a total of 65 times, 5 a total of 11 times, the 6 a total of 12 times and 8 just 4 times. You are not capped at 60 games while in aqua.

There are still 4 more tabs. I'll get to them in the next post.

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Re: [vpFREE] Re: A Keno Math Problem

 

I think I am beginning to understand this problem. Without the guarantee you are right Harry this is a complex problem that can't be solved in closed form. Without the guarantee let P(n) stand for the probability that in your last n games you have a 60 game losing streak. It is obvious that P(n) = P(n-1) + ((1-P(n-61))x(0.04324789135)x(0.070463738969)). This involves solving a 61st degree polynomial which can not be solved in closed form. To get you started P(60) = 0.070463738969, P(61) = P(60) + (0.04324789135)x(0.070463738969) = 0.07351114706. Years ago I solved the problem of a baseball team in n games having a 2 game winning (or losing) streak with the probability of a win or a loss a constant with independence of games. This involved solving a cubic equation which can be solved. It still took me a few days to put this in closed form. Good luck on this one Mickey!

Sent from my iPhone

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Re: [vpFREE] Re: A Keno Math Problem

 

This is some of the stuff a hardcore AP will put himself through to make a buck. I'll try to describe this game using the 7-spot as an example with everything at reset.

In the top left corner is a box with three features in it:

Free Games.....5
Multiplier...........2
Extra Draws......3

There is a progressive meter on the top right that starts with 20 bets in it.

When you are playing your 7 spot the machine makes 4 picks that are not part of your numbers. When that 4 spot hits, one of 4 things is going to happen:

If there is a star next to Free Games, Multiplier, and Extra Draws you are award 5 free games with a 2X multiplier, and 3 extra draws.

If there is only a star next to Free Games and Extra Draws then you are awarded 5 free games with 3 extra draws.

If there is only a star next to Free Games and Multiplier then you are awarded 5 free games with a 2X multiplier.

If the are no stars present then you are awarded the progressive meter that starts at 20 bets.

There is a lot more to come. Next post.

If there are no stars next to

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Re: [vpFREE] My Casino Henderson

 

It was called Mystic Casino until they were forced to changed their name
because there was already a casino named Mystic (I think in the Iowa area).
At that time they changed their name to MY. They are located way out
Boulder Hwy in Henderson.


In a message dated 4/8/2015 6:58:06 P.M. Eastern Daylight Time,
vpFREE@yahoogroups.com writes:

What is this place? I have never heard of it.

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RE: [vpFREE] My Casino Henderson

 

What is this place? I have never heard of it.

From: vpFREE@yahoogroups.com [mailto:vpFREE@yahoogroups.com]
Sent: Wednesday, April 08, 2015 12:43 PM
To: vpFREE@yahoogroups.com
Subject: [vpFREE] My Casino Henderson

Notices in the casino say the casino will close for business at midnight
April 23rd. Employees were just notified yesterday. Any points will expire
if not redeemed before the closing. Word is the casino was sold and the new
owners are going to do a complete renovation.

Down the road, I seem the former Terrible's Town Casino and Bowling building
is under construction. I haven't heard if it's going to be another casino.

Sent from my iPhone

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Posted by: "Scot Krause" <krauseinvegas@cox.net>
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