Come on, this is simple 9th grade math. Assuming independence of games the chance of hitting exactly 3 out of 4 is 1/23.12251462 - therefore the probability of not getting exactly 3 out of 4 is 0.95675210865 and the chance of going 60 consecutive games without exactly 3 out of 4 is (0.95675210865)**60 = 0.070463738969 or about 1/14.19169653. Two questions - do you get to leach on previous misses? In other words if the machine has gone 58 games without 3 out of 4 you are guaranteed 3 out of 4 by your 3rd try? Can you make small bets until you don't hit for 60 consecutive games and then bet the max on the next game when you will be awarded 3 out of 4?
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Posted by: nordo123@aol.com
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