The probability of 60 games without a hit is "simple math"
The frequency of a 60 game drought over successive 60 game trials is also "simple math"
The frequency of a 60 game drought over successive individual game trials is, I believe, strikingly more complex math. I'd welcome an argument to convince me otherwise.
---In vpFREE@yahoogroups.com, <Nordo123@...> wrote :
Come on, this is simple 9th grade math. Assuming independence of games the chance of hitting exactly 3 out of 4 is 1/23.12251462 - therefore the probability of not getting exactly 3 out of 4 is 0.95675210865 and the chance of going 60 consecutive games without exactly 3 out of 4 is (0.95675210865)**60 = 0.070463738969 or about 1/14.19169653.
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Posted by: harry.porter@verizon.net
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