[vpFREE] RE: Dealt Royal Progressive

 

To be a bit more anal, the probability of hitting the triple play jackpot is a bit higher than 1 in 649,740.   There will be a small chance you can get 4 to a Royal and make all 3 Royals:  The probability of that happening is:  4*5*47/2,598,960/47^3 = 1 in 287,055,132.  Adding this to the dealt royal probability of 1 in 649,740 leads to:  1 in 648,273.  Obviously you can extend this argument for 3 to Royal draws and less...but that's really splitting hairs, and the probability will barely change beyond this.





---In vpfree@yahoogroups.com, <pyiddy@...> wrote:

Thank You tendimes

From: 007 <007@...>
To: vpFREE@yahoogroups.com
Sent: Sunday, November 17, 2013 4:27 PM
Subject: Re: [vpFREE] RE: Dealt Royal Progressive
 
For a triple play, Howard's formula would be ($9,121.75 - $3000) /
(649,740*$1.25*3). Each $243 or so above the total of the 3 main
meters adds .01%.

tendimes34@... wrote:

>Thanks, I might be overanalyzing this and thus confusing myself but for triple play do we apply to all 3 lines or take the progressive and back out 3k since we are really only playing one hand?
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>---In vpfree@yahoogroups.com, <pyiddy@...> wrote:
>
> You have basically answered your own question. Since your holds do not affect this, if you are playing 5 coin 25c for example, the average cycle for one of these would be $812,175 for a dealt royal (649,740*$1.25).
> That would be the denominator and the numerator would be the current progressive minus $1,000. EG. A progressive of $9,121.75 ($1,000+$8,121.75) would add 1% to the game.
>
> Howard W. Stern
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>
> From: "tendimes34@..." <tendimes34@...>
> To: vpFREE@yahoogroups.com
> Sent: Sunday, November 17, 2013 4:17 AM
> Subject: [vpFREE] Dealt Royal Progressive
>
> hi - newbie here looking for some help from the stronger math players. How do I calculate breakeven for a dealt royal progressive? Is there a simple rule to apply like there is w/standard royal progressives where x amount above 4000 coins ='s x% to add to the payback %? Thanks in advance for any help you can provide.
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