Frank wrote:
> ---------------------------------------
> the7thwarrior
> So if a progressive is at 106% and there are 5 people playing, I
> figure it like this, only ONE person can hit that progressive. So
> 106% minus the base game say 96%, you have 10% extra due to the
> progressive, divided by the 5 people playing, you have a 2% edge
> added to the base game which makes it 98%...
> ------------------------------------------
>
> Could one of the lurking math gurus out there please answer this
> for me. For the second time in a week I'm at a loss for words.
>
> No contest this time, just my gratitude.
This takes a bit of common sense ... not "guru" math ...
The "106%" ER is the average expected return for all play on the bank -- winning and losing ... not just the return expected by the one who successfully hits the progressive (that win, when expressed as a percentage of wagers over the course of session(s), will likely by higher.
If one were to apply 7thwarrior's "methodology", the one player on a bank of 5 players who can be expected to hit the progressive might be looking at an ER of something north of 150%, while the other unsuccessful players are looking at something south of 93%.
[vpFREE] Re: Bob and Frank's new Progressives for suckers are in
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