Re: [vpFREE] poker math

 

The probability of not receiving dealt trips is 1-(1/46.3). Since hands are
independent, the probability of not receiving dealt trips in two hands is
the square of this value, in the three hands is the cube of this value, and
so on. So assuming hands, I get the odds to be 167565075937230.

On Sat, Mar 26, 2011 at 9:56 AM, Jeff McDaniel <jmcdaniel@dmtechlaw.com>wrote:

>
>
> I have a question for the math folks. If I understand the calculations
> correctly, on the deal, I will receive dealt trips about once every 46.3
> hands. I was recently playing and did not receive dealt trips for about an
> hour and a half. Assume I play 1,000 hands per hour, so I received 1 dealt
> trip in 1,500 trials. How unusual was that result? Is standard deviation the
> proper way to determine/express how unusual the result was? Is there a
> website you can point me to help me learn how to perform the calculation
> myself? Many thanks in advance for your help. Jeff
>
>
>

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