Re: [vpFREE] Re: what's % of losing hands. DDB 9/6

 

Or 1000 - (n<=1000).

Thx.


------ Original message------
Date: Mon, Feb 13, 2017 16:57
To: h_dunbar@hotmail.com [vpFREE];
Cc:
Subject:Re: [vpFREE] Re: what's % of losing hands. DDB 9/6

Oh. Sorry. Now I get it. A 1000 - 12 long interval, as opposed to an interval of length 12.

Sent from my LG K10, an AT&T 4G LTE smartphone

------ Original message------
Date: Mon, Feb 13, 2017 16:55
To: h_dunbar@hotmail.com [vpFREE];
Cc:
Subject:Re: [vpFREE] Re: what's % of losing hands. DDB 9/6

The 1000 as opposed to the 'n' aspect of it.

Thx.

Sent from my LG K10, an AT&T 4G LTE smartphone

------ Original message------
Date: Mon, Feb 13, 2017 16:44
To: h_dunbar@hotmail.com [vpFREE];
Cc:
Subject:Re: [vpFREE] Re: what's % of losing hands. DDB 9/6

"BUT, those are the probabilities of hitting blanks on your first "n" hands or your next "n" hands.   If you're wondering about, say, losing 12 straight hands some time during a 1000-hand play, then the probabilities would be much higher because you've got 988 possible starting points for your bad streak.

--Dunbar"

Can I possibly get you to lay that out mathematically with possibly a little accompanying explanation? I just can't get a handle on it.

Thx.

------ Original message------
From: h_dunbar@hotmail.com [vpFREE]
Date: Sun, Feb 5, 2017 05:27
Cc:
Subject:[vpFREE] Re: what's % of losing hands. DDB 9/6

 

"What is unusual number of losses in row, same game [9/6DDB]?  Would 8, 10 or 12 losing games in row be unusual?"


The chance of getting "nothing" in the 9/6 DDB pay table is 55.28%.   

The chance of getting nothing twice in a row is 55.28% x 55.28% = 30.56%
The chance of getting nothing 3 times in a row is 55.28% x 55.28% x 55.28% = 16.89%
and so on...

Stick =55.28%^8 into any spreadsheet, and you'll find that the chance of hitting blanks on your next 8 hands is 0.87%, about one in 115.

Here are some values (that'll probably format miserably):

streak 1 2 3 4 5 6 7 8 9 10 11 12
chance 55.28% 30.56% 16.89% 9.34% 5.16% 2.85% 1.58% 0.87% 0.48% 0.27% 0.15% 0.08%
1 in … 1.8 3.3 6 11 19 35 63 115 207 375 679 1228

BUT, those are the probabilities of hitting blanks on your first "n" hands or your next "n" hands.   If you're wondering about, say, losing 12 straight hands some time during a 1000-hand play, then the probabilities would be much higher because you've got 988 possible starting points for your bad streak.

--Dunbar


---In vpFREE@yahoogroups.com, wrote :

Good afternoon folks.


Say we play 1000 hands, what is the theoretical loss %?   9/6 DDB. I'm thinking if average is ,say, 55% loss then  550 of 1000 would be losers.  Thats assuming I'm thinking right.


What is unusual number of losses in row, same game?  Would 8, 10 or 12 losing games in row be unusual? 


Hoping someone has the info at their finger tips?

 


Cheers.....Jeep

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