Your question, particularly your use of the word "approach," is too vague to answer. You can determine how many standard deviations from expected value your result was, and I'll guess it was about 2, but, since you already knew you had bad luck, I don't think that tells you much.
On Tue, Dec 6, 2016 at 11:18 AM, stut70@yahoo.com [vpFREE] <vpFREE@yahoogroups.com> wrote:
$0.25 single line 99% Double Joker vp.
four $5k coin-in days = $20k coin-in.
$5k coin-in = 500 tc
It cost me $2000 for 2000 tc. :(
$2k lost/$20k coin-in = 10% loss = 90% return
$20k coin-in on a .25 machine = 16k hands.
On avg, how many hands are needed to approach the machine's 99% return?
thx
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Posted by: Thomas Robertson <007kzq@gmail.com>
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