It would seem to me, along that line of reasoning, you would also need to know how many aces filled on the next hand's draw.
< Sorry ... couldn't resist ... acting a bit of a smartass this a.m. ;>
Given the specific question asked, I think Jeff nailed it. (IOW, in the course of 26 mil hands, you expect one set of back to back quad Aces on average in 8/5 BP.)
- H.
--- In vpFREE@yahoogroups.com, ERNIE NELMIDA <been2all50@...> wrote:
>
> To accurately calculate the odds, we need to know how many aces the player held on the next hand resulting to another 4 aces.
>
>
>
>
> ________________________________
> From: jeffcole2003oct <jeff-cole@...>
> To: vpFREE@yahoogroups.com
> Sent: Monday, December 10, 2012 9:53 PM
> Subject: [vpFREE] Re: Odds of back to back Aces
>
>
> Â
> I believe Ernie's answer is for back-to-back dealt aces. Dealt aces have a cycle of 54,145. 4 aces for 8/5 BP have a cycle of about 5108.4, so square that to get about 26,095,751 hands.
> ====
> ERNIE NELMIDA wrote:
> That would be 1 in 2,931,681,025
> ====
> Last night at the Seminole Hard Rock in Hollywood my was playing $2 8/5 BP. She hit 4 Aces on back to back hands. Can anyone tell me what the odds are of that happening? Thanks.
> Frank
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