It's not a question of Alan's "dumbness". He's simply blind sighted by what, in his eyes, must be a 1:6 probability.
He sees that if you have information about only one of the dice after the roll, the other one must have a 1:6 chance of showing any given value.
Laying out the possible rolls that fit the description of the problem, each having equal probability (as a 5th grader might), isn't persuasive to him in the least. And he (and sidekick RS) are quick to point out that this isn't a multiple roll event, but a one shot result.
---In vpFREE@yahoogroups.com, <Nordo123@...> wrote :
I can't believe that there are so many posts on this. It is simple 5th grade probability. Alan can't be that dumb (can he?). I do have an out (forgive my poker terminology): Alan can say he wanted the 2 dice labeled 1 and 2, the dice to be rolled simultaneously and if die 1 showed a 2 the chance that the other die (die 2) would show a 2 would be 1 in 6.
Sent from my iPhone
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Posted by: harry.porter@verizon.net
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